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Popular >

midpoint (3,8),(1,-4)

Solution

midpoint

(3, 8), (1, - 4)

Solution

(2, 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (3, 8), (x_{2}, y_{2}) = (1, - 4)

= (\frac{1 + 3}{2}, \frac{- 4 + 8}{2})

Refine

= (2, 2)

Popular Examples

symmetry x^2-4x+4 symmetry

x^{2} - 4 x + 4

critical f(x)=-1+4x-x^3 critical points

f (x) = - 1 + 4 x - x^{3}

extreme f(x)=x+(17)/x extreme points

f (x) = x + \frac{17}{x}

distance (8,6),(-4,-3)distance

(8, 6), (- 4, - 3)

asymptotes of f(x)=(-x^2-5x+2)/(x+3)asymptotes

f (x) = \frac{- x ^{2} - 5 x + 2}{x + 3}

Frequently Asked Questions (FAQ)

What is the midpoint (3,8),(1,-4) ?
The midpoint (3,8),(1,-4) is (2,2)