What is the extreme f(x)=3x^4+12x^3 ?

The extreme f(x)=3x^4+12x^3 is Minimum(-3,-81),Saddle(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=3x^4+12x^3

extreme points

f (x) = 3 x^{4} + 12 x^{3}

Minimum (- 3, - 81), Saddle (0, 0)

Solution steps

f^{'} (x) = 12 x^{3} + 36 x^{2}

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 3

into

3 x^{4} + 12 x^{3} : - 81

Minimum (- 3, - 81)

Plug

x = 0

into

3 x^{4} + 12 x^{3} : 0

Saddle (0, 0)

Minimum (- 3, - 81), Saddle (0, 0)

\frac{5 e ^{x}}{e ^{x} - 9}

f (x) = \frac{( x - 2 )}{( x + 3 )}

- \frac{1}{7} sin (5 x + \frac{π}{2})

f (x) = \frac{- 7}{- 2 x - 4}

f (x) = \frac{2 x + 1}{1 - 3 x}

What is the extreme f(x)=3x^4+12x^3 ?
The extreme f(x)=3x^4+12x^3 is Minimum(-3,-81),Saddle(0,0)