What is the critical f(x)=x-3x^{1/3} ?

The critical f(x)=x-3x^{1/3} is x=-1,x=0,x=1

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critical f(x)=x-3x^{1/3}

critical points

f (x) = x - 3 x^{\frac{1}{3}}

x = - 1, x = 0, x = 1

Solution steps

x - 3 x^{\frac{1}{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1, x = 0

Identify critical points not in

f (x)

domain

Domain of

x - 3 x^{\frac{1}{3}} : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 0, x = 1

(- 4, 3), (4, - 1)

x^{2} + 6 x + 8

f (x) = - 3 x^{2} + 2

f (x) = (1 - x)^{3}

f (x) = \frac{1 - x}{4 x - 3}

What is the critical f(x)=x-3x^{1/3} ?
The critical f(x)=x-3x^{1/3} is x=-1,x=0,x=1