What is the inverse of f(x)=\sqrt[3]{x-2}+1 ?

The inverse of f(x)=\sqrt[3]{x-2}+1 is x^3-3x^2+3x+1

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inverse of f(x)=\sqrt[3]{x-2}+1

inverse

x^{3} - 3 x^{2} + 3 x + 1

Solution steps

Replace

x

with

y

Solve for

x^{3} - 3 x^{2} + 3 x + 1

f (x) = \frac{x}{x - 1}

cot (3 θ) + 5

f (x) = x^{2} - 5 x + (\frac{4}{x - 2})

f (x) = (x - 4) (x + 1)^{2} (x - 5)

x - x^{2}

What is the inverse of f(x)=\sqrt[3]{x-2}+1 ?
The inverse of f(x)=\sqrt[3]{x-2}+1 is x^3-3x^2+3x+1