What is the critical f(x)=x^7-7x^5 ?

The critical f(x)=x^7-7x^5 is x=-sqrt(5),x=0,x=sqrt(5)

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critical f(x)=x^7-7x^5

critical points

f (x) = x^{7} - 7 x^{5}

x = - 5, x = 0, x = 5

Solution steps

x^{7} - 7 x^{5}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 5, x = 0, x = 5

Identify critical points not in

f (x)

domain

Domain of

x^{7} - 7 x^{5} : - \infty < x < \infty

All critical points are in domain

x = - 5, x = 0, x = 5

f (x) = 9 - x

f (x) = ∣ x^{2} - 1 ∣

f (x) = \frac{1}{11.25 x} - \frac{1}{90}

g (x) = 2 x + 4

f (x) = \frac{x + 4}{x - 1}

What is the critical f(x)=x^7-7x^5 ?
The critical f(x)=x^7-7x^5 is x=-sqrt(5),x=0,x=sqrt(5)