What is the range of f(x)=sqrt(9-x) ?

The range of f(x)=sqrt(9-x) is f(x)>= 0

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range of f(x)=sqrt(9-x)

range

f (x) = 9 - x

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

f (x) = ∣ x^{2} - 1 ∣

f (x) = \frac{1}{11.25 x} - \frac{1}{90}

g (x) = 2 x + 4

f (x) = \frac{x + 4}{x - 1}

f (x) = \frac{\frac{x}{x + 1}}{\frac{x}{x + 1} + 1}