What is the domain of f(x)=((x^4))/(x^2+x-12) ?

The domain of f(x)=((x^4))/(x^2+x-12) is x 3

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domain of f(x)=((x^4))/(x^2+x-12)

domain

f (x) = \frac{( x ^{4} )}{x ^{2} + x - 12}

x < - 4 or - 4 < x < 3 or x > 3

Interval Notation

(- \infty, - 4) \cup (- 4, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 4

The function domain

x < - 4 or - 4 < x < 3 or x > 3

f (x) = 5 sin (\frac{2}{3} x + \frac{2}{9} π)

f (x) = \frac{x ^{2} + x - 6}{x - 3}

f (x) = x^{4} e^{x} - 4

25 - x^{2}

\frac{ln ( x - 3 )}{ln ( e ^{x} - e ^{3} )}

What is the domain of f(x)=((x^4))/(x^2+x-12) ?
The domain of f(x)=((x^4))/(x^2+x-12) is x<-4\lor-4<x<3\lor x>3