What is the inverse of \sqrt[3]{x+8}-6 ?

The inverse of \sqrt[3]{x+8}-6 is x^3+18x^2+108x+208

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inverse of \sqrt[3]{x+8}-6

inverse

x^{3} + 18 x^{2} + 108 x + 208

Solution steps

Replace

x

with

y

Solve for

x^{3} + 18 x^{2} + 108 x + 208

\frac{x + 1}{x - 1}

\frac{5 x}{x ^{2} - 16}

f (x) = arccos (\frac{( 1 - 2 x )}{4})

f (x) = \frac{( x )}{3 x ^{2} + 2 x - 1}

y = x + 7

What is the inverse of \sqrt[3]{x+8}-6 ?
The inverse of \sqrt[3]{x+8}-6 is x^3+18x^2+108x+208