What is the critical f(x)=4sqrt(x)-x^2 ?

The critical f(x)=4sqrt(x)-x^2 is x=0,x=1

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critical f(x)=4sqrt(x)-x^2

critical points

f (x) = 4 x - x^{2}

x = 0, x = 1

Solution steps

4 x - x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 1, x = 0

Identify critical points not in

f (x)

domain

Domain of

4 x - x^{2} : x \geq 0

All critical points are in domain

x = 0, x = 1

f (x) = 2^{x + 1} - 1

f (x) = \frac{3 x + 1}{1 - 7 x}

x + 4

2 x^{3} + 5

x^{3} - 3 x^{2} - 72 x

What is the critical f(x)=4sqrt(x)-x^2 ?
The critical f(x)=4sqrt(x)-x^2 is x=0,x=1