What is the domain of h(t)=(t^2-4t+2)/(t^2-5) ?

The domain of h(t)=(t^2-4t+2)/(t^2-5) is t sqrt(5)

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domain of h(t)=(t^2-4t+2)/(t^2-5)

domain

h (t) = \frac{t ^{2} - 4 t + 2}{t ^{2} - 5}

t < - 5 or - 5 < t < 5 or t > 5

Interval Notation

(- \infty, - 5) \cup (- 5, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

t = 5, t = - 5

The function domain

t < - 5 or - 5 < t < 5 or t > 5

f (x) = - x^{3} + 3 x^{2} - 2

26 sin (0.5 x - 2) + 68

f (x) = 17

f (x) = \frac{4 x - 3}{6 - 3 x}

cos (x + \frac{π}{2})

What is the domain of h(t)=(t^2-4t+2)/(t^2-5) ?
The domain of h(t)=(t^2-4t+2)/(t^2-5) is t<-sqrt(5)\lor-sqrt(5)<t<sqrt(5)\lor t>sqrt(5)