What is the domain of 1/((sqrt(x))/(x^2-4)) ?

The domain of 1/((sqrt(x))/(x^2-4)) is 0 2

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domain of 1/((sqrt(x))/(x^2-4))

domain

\frac{1}{\frac{x}{x ^{2} - 4}}

0 < x < 2 or x > 2

Interval Notation

(0, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 0, x = 2, x = - 2

Combine real regions and undefined points for final function domain

0 < x < 2 or x > 2

f (x) = - 1

\frac{x + 3}{x ^{2} - 9}

f (x) = \frac{4 x ^{2} - 1}{2 x - 1}

y = \frac{1}{3} x - 2, (3, - 3)

3 y = - 9 x + 15

What is the domain of 1/((sqrt(x))/(x^2-4)) ?
The domain of 1/((sqrt(x))/(x^2-4)) is 0<x<2\lor x>2