What is the asymptotes of f(x)=(x+1)/(x^2-3x-4) ?

The asymptotes of f(x)=(x+1)/(x^2-3x-4) is Vertical: x=4,Horizontal: y=0

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asymptotes of f(x)=(x+1)/(x^2-3x-4)

asymptotes

f (x) = \frac{x + 1}{x ^{2} - 3 x - 4}

Vertical : x = 4, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x + 1}{x ^{2} - 3 x - 4} : x = 4

Horizontal Asymptotes of

\frac{x + 1}{x ^{2} - 3 x - 4} : y = 0

Slant Asymptotes of

\frac{x + 1}{x ^{2} - 3 x - 4} :

None

Vertical : x = 4, Horizontal : y = 0

f (x) = lo g_{4} (16 x)

(\frac{1}{x})^{2} - 4 (\frac{1}{x})

y = - 7 x + 42, (7, - 8)

\frac{4 x - 3}{- 4 x + 2}

f (x) = \frac{x ^{2}}{x - 2}

What is the asymptotes of f(x)=(x+1)/(x^2-3x-4) ?
The asymptotes of f(x)=(x+1)/(x^2-3x-4) is Vertical: x=4,Horizontal: y=0