What is the perpendicular y=-7x+42,(7,-8) ?

The perpendicular y=-7x+42,(7,-8) is y= 1/7 x-9

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perpendicular y=-7x+42,(7,-8)

perpendicular

y = - 7 x + 42, (7, - 8)

y = \frac{1}{7} x - 9

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 7 x + 42

that passes through

(7, - 8)

Find the slope of

y = - 7 x + 42 : m = - 7

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{7}

Find the line with slope m=

\frac{1}{7}

and passing through

(7, - 8) : y = \frac{1}{7} x - 9

y = \frac{1}{7} x - 9

\frac{4 x - 3}{- 4 x + 2}

f (x) = \frac{x ^{2}}{x - 2}

f (x) = x^{5} - 9 x^{3} + 9 x

f (x) = \frac{1}{8 x - 16}

5 x^{4} + 20 x^{3}

What is the perpendicular y=-7x+42,(7,-8) ?
The perpendicular y=-7x+42,(7,-8) is y= 1/7 x-9