What is the extreme f(x)=(x^2)/(x-2) ?

The extreme f(x)=(x^2)/(x-2) is Maximum(0,0),Minimum(4,8)

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extreme f(x)=(x^2)/(x-2)

extreme points

f (x) = \frac{x ^{2}}{x - 2}

Maximum (0, 0), Minimum (4, 8)

Solution steps

f^{'} (x) = \frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Decreasing

: 2 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 0

into

\frac{x ^{2}}{x - 2} : 0

Maximum (0, 0)

Plug

x = 4

into

\frac{x ^{2}}{x - 2} : 8

Minimum (4, 8)

Maximum (0, 0), Minimum (4, 8)

f (x) = x^{5} - 9 x^{3} + 9 x

f (x) = \frac{1}{8 x - 16}

5 x^{4} + 20 x^{3}

f (x) = 2^{x + 3}

\frac{1}{3} x^{3} + 2 x^{2} - 5 x + \frac{8}{3}

What is the extreme f(x)=(x^2)/(x-2) ?
The extreme f(x)=(x^2)/(x-2) is Maximum(0,0),Minimum(4,8)