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Popular >

range of f(x)=-6x^2+10x-7

Solution

range

f (x) = - 6 x^{2} + 10 x - 7

Solution

f (x) \leq - \frac{17}{6}

+1

Interval Notation

(- \infty, - \frac{17}{6}]

Solution steps

Vertex of

- 6 x^{2} + 10 x - 7 :

Maximum

(\frac{5}{6}, - \frac{17}{6})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 6,

Vertex

(x_{v}, y_{v}) = (\frac{5}{6}, - \frac{17}{6})

f (x) \leq - \frac{17}{6}

Popular Examples

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\frac{x ^{3} - 1}{x ^{2} + 2 x - 3}

midpoint (-5/2 , 1/2),(-15/2 ,-13/2)midpoint

(- \frac{5}{2}, \frac{1}{2}), (- \frac{15}{2}, - \frac{13}{2})

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inflection f(x)=3x^{2/3}-2x inflection points

f (x) = 3 x^{\frac{2}{3}} - 2 x

domain of 4-x^2 domain

4 - x^{2}

Frequently Asked Questions (FAQ)

What is the range of f(x)=-6x^2+10x-7 ?
The range of f(x)=-6x^2+10x-7 is f(x)<=-17/6