What is the domain of f(x)=4+7sqrt(25-x^2) ?

The domain of f(x)=4+7sqrt(25-x^2) is -5<= x<= 5

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domain of f(x)=4+7sqrt(25-x^2)

domain

f (x) = 4 + 7 25 - x^{2}

- 5 \leq x \leq 5

Interval Notation

[- 5, 5]

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq 5

The function domain

- 5 \leq x \leq 5

f (x) = 1 - 9 x

f (x) = \frac{1}{( x - 8 ) ^{2}} + 9

6 x + 2

f (x) = 6 x + 6

What is the domain of f(x)=4+7sqrt(25-x^2) ?
The domain of f(x)=4+7sqrt(25-x^2) is -5<= x<= 5