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Popular >

distance (4,1.5),(4.5,3.5)

Solution

distance

(4, 1.5), (4.5, 3.5)

Solution

2.06155 \dots

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(4, 1.5)

and

(4.5, 3.5)

is

= (4.5 - 4)^{2} + (3.5 - 1.5)^{2}

Simplify

= 2.06155 \dots

Popular Examples

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3 x + 6 y = 12, at

line (2,4),(5,-4)line

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critical (ln(x))/(x^2)critical points

\frac{ln ( x )}{x ^{2}}

periodicity of f(x)=cos(2x+pi)periodicity

f (x) = cos (2 x + π)

range of 9-x^2 range

9 - x^{2}

Frequently Asked Questions (FAQ)

What is the distance (4,1.5),(4.5,3.5) ?
The distance (4,1.5),(4.5,3.5) is 2.06155…