What is the inverse of f(x)=(3x-1)/(2x+8) ?

The inverse of f(x)=(3x-1)/(2x+8) is (-1-8x)/(2x-3)

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inverse of f(x)=(3x-1)/(2x+8)

inverse

f (x) = \frac{3 x - 1}{2 x + 8}

\frac{- 1 - 8 x}{2 x - 3}

Solution steps

y = \frac{3 x - 1}{2 x + 8}

Replace

x

with

y

x = \frac{3 y - 1}{2 y + 8}

Solve for

y, x = \frac{3 y - 1}{2 y + 8}

\frac{- 1 - 8 x}{2 x - 3}

f (x) = 5 x^{2} - 1

\frac{1}{x ^{2} + 2 x + 2}, - 2 \leq x \leq 2

3 x - 10 y = 20

(- 1, 4), (4, - 2)

f (x) = x^{2} + x

What is the inverse of f(x)=(3x-1)/(2x+8) ?
The inverse of f(x)=(3x-1)/(2x+8) is (-1-8x)/(2x-3)