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Popular >

range of f(x)=8x^2+3

Solution

range

f (x) = 8 x^{2} + 3

Solution

f (x) \geq 3

+1

Interval Notation

[3, \infty)

Solution steps

Vertex of

8 x^{2} + 3 :

Minimum

(0, 3)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 8,

Vertex

(x_{v}, y_{v}) = (0, 3)

f (x) \geq 3

Popular Examples

periodicity of f(x)=-1+3cos(2x)periodicity

f (x) = - 1 + 3 cos (2 x)

inverse of 0.23log_{10}(x)inverse

0.23 lo g_{10} (x)

inverse of f(x)=(2x+1)/(3x+4)inverse

f (x) = \frac{2 x + 1}{3 x + 4}

inverse of f(x)=x^2-4x+3 inverse

f (x) = x^{2} - 4 x + 3

critical 4x^3-24x^2+36x critical points

4 x^{3} - 24 x^{2} + 36 x

Frequently Asked Questions (FAQ)

What is the range of f(x)=8x^2+3 ?
The range of f(x)=8x^2+3 is f(x)>= 3