What is the domain of f(x)=sqrt(x+5)+sqrt(3-2x) ?

The domain of f(x)=sqrt(x+5)+sqrt(3-2x) is -5<= x<= 3/2

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domain of f(x)=sqrt(x+5)+sqrt(3-2x)

domain

f (x) = x + 5 + 3 - 2 x

- 5 \leq x \leq \frac{3}{2}

Interval Notation

[- 5, \frac{3}{2}]

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq \frac{3}{2}

The function domain

- 5 \leq x \leq \frac{3}{2}

f (x) = x^{2} - 8 x + 7

\frac{( x ^{2} + x )}{2}

f (x) = \frac{1}{3 + e ^{2 x}}

x^{2} - 2 x + 3

f (x) = x^{2} - 5 x

What is the domain of f(x)=sqrt(x+5)+sqrt(3-2x) ?
The domain of f(x)=sqrt(x+5)+sqrt(3-2x) is -5<= x<= 3/2