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Popular >

range of x^2+2x-8

Solution

range

x^{2} + 2 x - 8

Solution

f (x) \geq - 9

+1

Interval Notation

[- 9, \infty)

Solution steps

Vertex of

x^{2} + 2 x - 8 :

Minimum

(- 1, - 9)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 1, - 9)

f (x) \geq - 9

Popular Examples

inverse of h(x)= 1/(x-1)inverse

h (x) = \frac{1}{x - 1}

extreme f(x)=-4x^3+6x^2-5 extreme points

f (x) = - 4 x^{3} + 6 x^{2} - 5

asymptotes of f(x)=2*3^{x-4}asymptotes

f (x) = 2 \cdot 3^{x - 4}

periodicity of f(x)= 5/3 sin(-(2pi)/3 x)periodicity

f (x) = \frac{5}{3} sin (- \frac{2 π}{3} x)

perpendicular y=8x-3,(6,2)perpendicular

y = 8 x - 3, (6, 2)

Frequently Asked Questions (FAQ)

What is the range of x^2+2x-8 ?
The range of x^2+2x-8 is f(x)>=-9