What is the domain of f(x)=2sqrt(x+1) ?

The domain of f(x)=2sqrt(x+1) is x>=-1

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domain of f(x)=2sqrt(x+1)

domain

f (x) = 2 x + 1

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

24000 x^{2} + 900 x - 150

\frac{x ^{2} - 16}{x + 4}

\frac{2}{3} x + 2 y = \frac{- 8}{3}, (- 5, 5)

- (x + 4) (x - 4) - x + 1

\frac{x + 1}{x - 1}