What is the critical f(x)=-x^3-3x^2+9x+3 ?

The critical f(x)=-x^3-3x^2+9x+3 is x=-3,x=1

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critical f(x)=-x^3-3x^2+9x+3

critical points

f (x) = - x^{3} - 3 x^{2} + 9 x + 3

x = - 3, x = 1

Solution steps

- x^{3} - 3 x^{2} + 9 x + 3

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 1

Identify critical points not in

f (x)

domain

Domain of

- x^{3} - 3 x^{2} + 9 x + 3 : - \infty < x < \infty

All critical points are in domain

x = - 3, x = 1

f (x) = x + 6

6 x + 3 y = - 6

f (x) = \frac{1 + 4 x}{2 x - 1}

(10.3) (4.7)

12 x^{2} - 204 x + 594

What is the critical f(x)=-x^3-3x^2+9x+3 ?
The critical f(x)=-x^3-3x^2+9x+3 is x=-3,x=1