What is the domain of f(x)=sqrt(9-t^2) ?

The domain of f(x)=sqrt(9-t^2) is -3<= t<= 3

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domain of f(x)=sqrt(9-t^2)

domain

f (x) = 9 - t^{2}

- 3 \leq t \leq 3

Interval Notation

[- 3, 3]

Solution steps

Find non-negative values for radicals:

- 3 \leq t \leq 3

The function domain

- 3 \leq t \leq 3

\frac{7}{3 + e ^{x}}

\frac{6 x}{7} \frac{4 x}{3}

(2019, - 560631), (2020, 5523594)

\frac{x ^{2} + 1}{2}

\frac{x ^{2} + 7 x}{5 x ^{2} - 1}

What is the domain of f(x)=sqrt(9-t^2) ?
The domain of f(x)=sqrt(9-t^2) is -3<= t<= 3