What is the critical f(x)=x^3-3x+5 ?

The critical f(x)=x^3-3x+5 is x=-1,x=1

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critical f(x)=x^3-3x+5

critical points

f (x) = x^{3} - 3 x + 5

x = - 1, x = 1

Solution steps

x^{3} - 3 x + 5

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

x^{3} - 3 x + 5 : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 1

f (x) = - \frac{1}{9} x + \frac{4}{3}

g (x) = 2 x - 1

(8, - 8.5), (8, - 6)

f (x) = \frac{( 1 + x ^{2} )}{( 2 + x ^{4} )}

(cos (9 x))^{x}