What is the inverse of f(x)=((17x-6))/((-9x-3)) ?

The inverse of f(x)=((17x-6))/((-9x-3)) is -(-6+3x)/(17+9x)

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inverse of f(x)=((17x-6))/((-9x-3))

inverse

f (x) = \frac{( 17 x - 6 )}{( - 9 x - 3 )}

- \frac{- 6 + 3 x}{17 + 9 x}

Solution steps

y = \frac{17 x - 6}{- 9 x - 3}

Replace

x

with

y

x = \frac{17 y - 6}{- 9 y - 3}

Solve for

y, x = \frac{17 y - 6}{- 9 y - 3}

- \frac{- 6 + 3 x}{17 + 9 x}

f (x) = \frac{10 e ^{2 x} + 8}{4 + e ^{2 x}}

f (x) = \frac{3 x - 7}{4 x - 7}

f (x) = lo g_{10} (\frac{x + 4}{2}) - 3

y = x^{2} - 6 x + 8

What is the inverse of f(x)=((17x-6))/((-9x-3)) ?
The inverse of f(x)=((17x-6))/((-9x-3)) is -(-6+3x)/(17+9x)