What is the inverse of g(x)=2\sqrt[3]{x-3}+4 ?

The inverse of g(x)=2\sqrt[3]{x-3}+4 is 6x+(x^3)/8-(3x^2)/2-5

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inverse of g(x)=2\sqrt[3]{x-3}+4

inverse

6 x + \frac{x ^{3}}{8} - \frac{3 x ^{2}}{2} - 5

Solution steps

Replace

x

with

y

Solve for

6 x + \frac{x ^{3}}{8} - \frac{3 x ^{2}}{2} - 5

f (x) = \frac{10 e ^{2 x} + 8}{4 + e ^{2 x}}

f (x) = \frac{3 x - 7}{4 x - 7}

f (x) = lo g_{10} (\frac{x + 4}{2}) - 3

y = x^{2} - 6 x + 8

What is the inverse of g(x)=2\sqrt[3]{x-3}+4 ?
The inverse of g(x)=2\sqrt[3]{x-3}+4 is 6x+(x^3)/8-(3x^2)/2-5