What is the inverse of f(x)=7(x-3)^{1/5} ?

The inverse of f(x)=7(x-3)^{1/5} is (x^5)/(16807)+3

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inverse of f(x)=7(x-3)^{1/5}

inverse

f (x) = 7 (x - 3)^{\frac{1}{5}}

\frac{x ^{5}}{16807} + 3

Solution steps

y = 7 (x - 3)^{\frac{1}{5}}

Replace

x

with

y

x = 7 (y - 3)^{\frac{1}{5}}

Solve for

y, x = 7 (y - 3)^{\frac{1}{5}}

\frac{x ^{5}}{16807} + 3

e^{1 - 4 x^{- 3}}

y = - x + 5

(x^{2} + 5 x)^{\frac{1}{2}}

f (x) = 1 - 2 + x

f (x) = 5 e^{x - 2} + 6

What is the inverse of f(x)=7(x-3)^{1/5} ?
The inverse of f(x)=7(x-3)^{1/5} is (x^5)/(16807)+3