What is the inverse of f(x)=x^2-3x-10 ?

The inverse of f(x)=x^2-3x-10 is (3+sqrt(4x+49))/2 ,(3-sqrt(4x+49))/2

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inverse of f(x)=x^2-3x-10

inverse

f (x) = x^{2} - 3 x - 10

\frac{3 + 4 x + 49}{2}, \frac{3 - 4 x + 49}{2}

Solution steps

y = x^{2} - 3 x - 10

Replace

x

with

y

x = y^{2} - 3 y - 10

Solve for

y, x = y^{2} - 3 y - 10

\frac{3 + 4 x + 49}{2}, \frac{3 - 4 x + 49}{2}

arcsec (\frac{2 3}{3})

5 y + 4 = (x + 3)^{2} + \frac{1}{2}

6 - x

What is the inverse of f(x)=x^2-3x-10 ?
The inverse of f(x)=x^2-3x-10 is (3+sqrt(4x+49))/2 ,(3-sqrt(4x+49))/2