What is the inverse of f(x)=((3-8x))/(4+7x) ?

The inverse of f(x)=((3-8x))/(4+7x) is (3-4x)/(7x+8)

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inverse of f(x)=((3-8x))/(4+7x)

inverse

f (x) = \frac{( 3 - 8 x )}{4 + 7 x}

\frac{3 - 4 x}{7 x + 8}

Solution steps

y = \frac{3 - 8 x}{4 + 7 x}

Replace

x

with

y

x = \frac{3 - 8 y}{4 + 7 y}

Solve for

y, x = \frac{3 - 8 y}{4 + 7 y}

\frac{3 - 4 x}{7 x + 8}

f (x) = 3 - 3 2 x - 1

f (x) = \frac{2 x ^{2} + 3}{5}

2 \cdot 3^{x} + 9^{x} + 3

p (x) = x^{2} + 1

f (x) = 5 \frac{x + 2}{4}

What is the inverse of f(x)=((3-8x))/(4+7x) ?
The inverse of f(x)=((3-8x))/(4+7x) is (3-4x)/(7x+8)