What is the inverse of f(x)=(3x^2+4)/8 ?

The inverse of f(x)=(3x^2+4)/8 is sqrt((8x-4)/3),-sqrt((8x-4)/3)

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inverse of f(x)=(3x^2+4)/8

inverse

f (x) = \frac{3 x ^{2} + 4}{8}

\frac{8 x - 4}{3}, - \frac{8 x - 4}{3}

Solution steps

y = \frac{3 x ^{2} + 4}{8}

Replace

x

with

y

x = \frac{3 y ^{2} + 4}{8}

Solve for

y, x = \frac{3 y ^{2} + 4}{8}

\frac{8 x - 4}{3}, - \frac{8 x - 4}{3}

y = \frac{x - 2}{3 x - 1}

f (x) = (x - 16)^{2}

f (x) = (5 x)^{- \frac{4}{3}}

y = ln (2 x - 3) - ln (x + 5) + 1

f (x) = 1 + 4 + 8 x

What is the inverse of f(x)=(3x^2+4)/8 ?
The inverse of f(x)=(3x^2+4)/8 is sqrt((8x-4)/3),-sqrt((8x-4)/3)