What is the inverse of f(x)=\sqrt[3]{x+3}+1 ?

The inverse of f(x)=\sqrt[3]{x+3}+1 is x^3-3x^2+3x-4

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inverse of f(x)=\sqrt[3]{x+3}+1

inverse

x^{3} - 3 x^{2} + 3 x - 4

Solution steps

Replace

x

with

y

Solve for

x^{3} - 3 x^{2} + 3 x - 4

f (x) = 5 x^{\frac{5}{2}}

f (x) = - \frac{4}{3 x ^{2}} + \frac{4}{3}

f (x) = 11 x^{3} - 8

f (x) = x^{2} - 16, x \geq 0

- 4 x + 1

What is the inverse of f(x)=\sqrt[3]{x+3}+1 ?
The inverse of f(x)=\sqrt[3]{x+3}+1 is x^3-3x^2+3x-4