What is the inverse of f(x)=x^2-4x-12 ?

The inverse of f(x)=x^2-4x-12 is 2+sqrt(x+16),2-sqrt(x+16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=x^2-4x-12

inverse

f (x) = x^{2} - 4 x - 12

2 + x + 16, 2 - x + 16

Solution steps

y = x^{2} - 4 x - 12

Replace

x

with

y

x = y^{2} - 4 y - 12

Solve for

y, x = y^{2} - 4 y - 12

2 + x + 16, 2 - x + 16

\frac{3}{2 x - 4}

f (x) = x^{0.75} + 40

f (x) = \frac{6 x}{x ^{2} - 1}

lo g_{6} (x + 2)

\frac{1}{3} lo g_{2} (x) + 1

What is the inverse of f(x)=x^2-4x-12 ?
The inverse of f(x)=x^2-4x-12 is 2+sqrt(x+16),2-sqrt(x+16)