What is the inverse of f(x)=(((x-1)^2))/(81) ?

The inverse of f(x)=(((x-1)^2))/(81) is 9sqrt(x)+1,-9sqrt(x)+1

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inverse of f(x)=(((x-1)^2))/(81)

inverse

f (x) = \frac{( ( x - 1 ) ^{2} )}{81}

9 x + 1, - 9 x + 1

Solution steps

y = \frac{( x - 1 ) ^{2}}{81}

Replace

x

with

y

x = \frac{( y - 1 ) ^{2}}{81}

Solve for

y, x = \frac{( y - 1 ) ^{2}}{81}

9 x + 1, - 9 x + 1

f (x) = (x - 8)^{2} + 1

2^{x + 3} - 5

g (x) = 4 x^{2} - 12

f (x) = \frac{2 - x}{2 + x}

f (x) = \frac{- 7}{8 + 3 x}

What is the inverse of f(x)=(((x-1)^2))/(81) ?
The inverse of f(x)=(((x-1)^2))/(81) is 9sqrt(x)+1,-9sqrt(x)+1