What is the inverse of f(x)=3(x-1)^2+2 ?

The inverse of f(x)=3(x-1)^2+2 is sqrt((x-2)/3)+1,-sqrt((x-2)/3)+1

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inverse of f(x)=3(x-1)^2+2

inverse

f (x) = 3 (x - 1)^{2} + 2

\frac{x - 2}{3} + 1, - \frac{x - 2}{3} + 1

Solution steps

y = 3 (x - 1)^{2} + 2

Replace

x

with

y

x = 3 (y - 1)^{2} + 2

Solve for

y, x = 3 (y - 1)^{2} + 2

\frac{x - 2}{3} + 1, - \frac{x - 2}{3} + 1

ln (5 x + 3)

f (x) = 10 x - 4

f (x) = \frac{4 x ^{3}}{5} - \frac{7}{6}

f (x) = \frac{1}{2} x^{2} + 2

f (x) = \frac{2 x + 3}{3 x - 7}

What is the inverse of f(x)=3(x-1)^2+2 ?
The inverse of f(x)=3(x-1)^2+2 is sqrt((x-2)/3)+1,-sqrt((x-2)/3)+1