What is the inverse of f(x)=18x-3x^2 ?

The inverse of f(x)=18x-3x^2 is -(-18+sqrt(324-12x))/6 ,-(-18-sqrt(324-12x))/6

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inverse of f(x)=18x-3x^2

inverse

f (x) = 18 x - 3 x^{2}

- \frac{- 18 + 324 - 12 x}{6}, - \frac{- 18 - 324 - 12 x}{6}

Solution steps

y = 18 x - 3 x^{2}

Replace

x

with

y

x = 18 y - 3 y^{2}

Solve for

y, x = 18 y - 3 y^{2}

- \frac{- 18 + 324 - 12 x}{6}, - \frac{- 18 - 324 - 12 x}{6}

\frac{1}{2} x - 1

ln (1 - 2 x)

f (x) = 3 x^{2} + 18 x + 20

f (x) = \frac{5 x + 6}{x + 5}

f (x) = \frac{1}{4} (x - 6)^{2} - 5, x \leq 6

What is the inverse of f(x)=18x-3x^2 ?
The inverse of f(x)=18x-3x^2 is -(-18+sqrt(324-12x))/6 ,-(-18-sqrt(324-12x))/6