What is the inverse of f(x)=3x^2+18x+20 ?

The inverse of f(x)=3x^2+18x+20 is (-18+sqrt(12x+84))/6 ,(-18-sqrt(12x+84))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=3x^2+18x+20

inverse

f (x) = 3 x^{2} + 18 x + 20

\frac{- 18 + 12 x + 84}{6}, \frac{- 18 - 12 x + 84}{6}

Solution steps

y = 3 x^{2} + 18 x + 20

Replace

x

with

y

x = 3 y^{2} + 18 y + 20

Solve for

y, x = 3 y^{2} + 18 y + 20

\frac{- 18 + 12 x + 84}{6}, \frac{- 18 - 12 x + 84}{6}

f (x) = \frac{5 x + 6}{x + 5}

f (x) = \frac{1}{4} (x - 6)^{2} - 5, x \leq 6

f (x) = \frac{x + 1}{2 x}

f (x) = \frac{x ^{3}}{3}

\frac{2 ^{x}}{1 + 2 ^{x}}

What is the inverse of f(x)=3x^2+18x+20 ?
The inverse of f(x)=3x^2+18x+20 is (-18+sqrt(12x+84))/6 ,(-18-sqrt(12x+84))/6