What is the inverse of f(x)=sqrt((5x^3-1)+7) ?

The inverse of f(x)=sqrt((5x^3-1)+7) is cube root of (x^2-6)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=sqrt((5x^3-1)+7)

inverse

f (x) = (5 x^{3} - 1) + 7

Solution steps

y = 5 x^{3} - 1 + 7

Replace

x

with

y

x = 5 y^{3} - 1 + 7

Solve for

y, x = 5 y^{3} - 1 + 7

\frac{2}{s ^{2} + 6 s + 8}

f (x) = - \frac{1}{3 x}

f (x) = \frac{( 2 x + 1 )}{( x - 3 )}

f (x) = \frac{( 2 x )}{( 3 x - 1 )}

f (x) = - \frac{5}{2} x + \frac{25}{2}

What is the inverse of f(x)=sqrt((5x^3-1)+7) ?
The inverse of f(x)=sqrt((5x^3-1)+7) is cube root of (x^2-6)/5