What is the inverse of f(x)=(x+1)(x-7) ?

The inverse of f(x)=(x+1)(x-7) is 3+sqrt(x+16),3-sqrt(x+16)

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inverse of f(x)=(x+1)(x-7)

inverse

f (x) = (x + 1) (x - 7)

3 + x + 16, 3 - x + 16

Solution steps

y = (x + 1) (x - 7)

Replace

x

with

y

x = (y + 1) (y - 7)

Solve for

y, x = (y + 1) (y - 7)

3 + x + 16, 3 - x + 16

\frac{( 2 x + 3 )}{( x + 2 )}

\frac{x + 2}{3 x - 4}

f (x) = x + x + 2, x > 2

g (x) = 3 x^{2} - 4

4 x + 16

What is the inverse of f(x)=(x+1)(x-7) ?
The inverse of f(x)=(x+1)(x-7) is 3+sqrt(x+16),3-sqrt(x+16)