What is the inverse of f(x)=((x+2))/(x-5) ?

The inverse of f(x)=((x+2))/(x-5) is (2+5x)/(x-1)

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inverse of f(x)=((x+2))/(x-5)

inverse

f (x) = \frac{( x + 2 )}{x - 5}

\frac{2 + 5 x}{x - 1}

Solution steps

y = \frac{x + 2}{x - 5}

Replace

x

with

y

x = \frac{y + 2}{y - 5}

Solve for

y, x = \frac{y + 2}{y - 5}

\frac{2 + 5 x}{x - 1}

g (x) = \frac{- x + 9}{7 + 4 x}

f (x) = lo g_{2} (7 x - 10)

y = 41 - 1.25 h

2 x^{2} - 12 x + 5

x + 3 - 9

What is the inverse of f(x)=((x+2))/(x-5) ?
The inverse of f(x)=((x+2))/(x-5) is (2+5x)/(x-1)