What is the inverse of f(x)=((17x-6))/(-9x-3) ?

The inverse of f(x)=((17x-6))/(-9x-3) is -(-6+3x)/(17+9x)

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inverse of f(x)=((17x-6))/(-9x-3)

inverse

f (x) = \frac{( 17 x - 6 )}{- 9 x - 3}

- \frac{- 6 + 3 x}{17 + 9 x}

Solution steps

y = \frac{17 x - 6}{- 9 x - 3}

Replace

x

with

y

x = \frac{17 y - 6}{- 9 y - 3}

Solve for

y, x = \frac{17 y - 6}{- 9 y - 3}

- \frac{- 6 + 3 x}{17 + 9 x}

f (x) = 7 (x^{\frac{1}{5}} + 7)

f (s) = \frac{1}{s ^{3} + a ^{3}}

f (x) = 5 x^{2} + 7

f (x) = 5 x^{2} + 4

4 (x - 11)^{2}

What is the inverse of f(x)=((17x-6))/(-9x-3) ?
The inverse of f(x)=((17x-6))/(-9x-3) is -(-6+3x)/(17+9x)