What is the domain of f(x)=log_{3}(2x-3) ?

The domain of f(x)=log_{3}(2x-3) is x> 3/2

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domain of f(x)=log_{3}(2x-3)

domain

f (x) = lo g_{3} (2 x - 3)

x > \frac{3}{2}

Interval Notation

(\frac{3}{2}, \infty)

Solution steps

Find positive values for logs:

x > \frac{3}{2}

The function domain

x > \frac{3}{2}

f (x) = \frac{1}{x + 3} - \frac{1}{( x + 3 ) ^{2}}

f (x) = \frac{2 x}{x - 4}

f (x) = x - 2 + 6 - x

2 x - 6

f (x) = 2 - x - x^{2}

What is the domain of f(x)=log_{3}(2x-3) ?
The domain of f(x)=log_{3}(2x-3) is x> 3/2