What is the domain of f(x)=sqrt((x-1))^2 ?

The domain of f(x)=sqrt((x-1))^2 is x>= 1

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domain of f(x)=sqrt((x-1))^2

domain

f (x) = (x - 1)^{2}

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

f (x) = \frac{1}{2 - x ^{2}}

\frac{x - 3}{x + 4}

f (x) = 2^{x} - 4

f (x) = \frac{x ^{2} + 2 x - 1}{2 x - 1}

f (x) = \frac{2 x - 7}{x ^{2} - 5 x + 4}

What is the domain of f(x)=sqrt((x-1))^2 ?
The domain of f(x)=sqrt((x-1))^2 is x>= 1