What is the domain of f(x)= x/(4x^2-9) ?

The domain of f(x)= x/(4x^2-9) is x 3/2

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domain of f(x)= x/(4x^2-9)

domain

f (x) = \frac{x}{4 x ^{2} - 9}

x < - \frac{3}{2} or - \frac{3}{2} < x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, - \frac{3}{2}) \cup (- \frac{3}{2}, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{2}, x = - \frac{3}{2}

The function domain

x < - \frac{3}{2} or - \frac{3}{2} < x < \frac{3}{2} or x > \frac{3}{2}

f (x) = \frac{2 x + 1}{2 x - 1}

f (x) = x^{2} + 7 x + 10

f (x) = - 2 x + 6

f (x) = \frac{1}{5.7 x - 8.1 x ^{2}}

x^{2} - 4 x + 7

What is the domain of f(x)= x/(4x^2-9) ?
The domain of f(x)= x/(4x^2-9) is x<-3/2 \lor-3/2 <x< 3/2 \lor x> 3/2