What is the domain of f(x)=sqrt(ln(26-9x^2)) ?

The domain of f(x)=sqrt(ln(26-9x^2)) is -5/3 <= x<= 5/3

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domain of f(x)=sqrt(ln(26-9x^2))

domain

f (x) = ln (26 - 9 x^{2})

- \frac{5}{3} \leq x \leq \frac{5}{3}

Interval Notation

[- \frac{5}{3}, \frac{5}{3}]

Solution steps

Find non-negative values for radicals:

- \frac{5}{3} \leq x \leq \frac{5}{3}

The function domain

- \frac{5}{3} \leq x \leq \frac{5}{3}

f (x) = \frac{x - 1}{2}

f (x) = \frac{x}{x ^{2} + 12 x + 35}

f (x) = 1 - x ln (x + 2)

f (x, y) = x^{2}

What is the domain of f(x)=sqrt(ln(26-9x^2)) ?
The domain of f(x)=sqrt(ln(26-9x^2)) is -5/3 <= x<= 5/3