What is the domain of f(x)=\sqrt[3]{x^3-4} ?

The domain of f(x)=\sqrt[3]{x^3-4} is -infinity <x<infinity

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domain of f(x)=\sqrt[3]{x^3-4}

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 1 - x ln (x + 2)

f (x, y) = x^{2}

f (x) = \frac{x + 2}{5}

f (x) = \frac{2 x ^{2} - 6 x + 4}{3 x - 5}

f (x) = \frac{4 - 3 x}{x + 5}

What is the domain of f(x)=\sqrt[3]{x^3-4} ?
The domain of f(x)=\sqrt[3]{x^3-4} is -infinity <x<infinity