What is the domain of f(v)=sqrt(1+7/x) ?

The domain of f(v)=sqrt(1+7/x) is x 0

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domain of f(v)=sqrt(1+7/x)

domain

f (v) = 1 + \frac{7}{x}

x \leq - 7 or x > 0

Interval Notation

(- \infty, - 7] \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 7 or x > 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x \leq - 7 or x > 0

f (x) = \frac{1}{2 x - 4}

\frac{x - 2}{x ^{2} - x}

f (x) = \frac{3 sin ( x )}{sin ( 2 x ) + 1}

\frac{x + 6}{x ^{2} - 9}

f (x) = - x^{2} - 13 x - 40

What is the domain of f(v)=sqrt(1+7/x) ?
The domain of f(v)=sqrt(1+7/x) is x<=-7\lor x>0