What is the domain of f(x)=sqrt(x^2-x-12) ?

The domain of f(x)=sqrt(x^2-x-12) is x = 4

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domain of f(x)=sqrt(x^2-x-12)

domain

f (x) = x^{2} - x - 12

x \leq - 3 or x \geq 4

Interval Notation

(- \infty, - 3] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 4

The function domain

x \leq - 3 or x \geq 4

y = \frac{2 x + 5}{9 x - 8}

y = \frac{x ^{4} - 16}{x ^{2} - 49}

y = x^{2} - 2

x e^{a x}

What is the domain of f(x)=sqrt(x^2-x-12) ?
The domain of f(x)=sqrt(x^2-x-12) is x<=-3\lor x>= 4