What is the domain of f(x)=2x^2+x+6,-3<= x<8 ?

The domain of f(x)=2x^2+x+6,-3<= x<8 is -3<= x<8

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domain of f(x)=2x^2+x+6,-3<= x<8

domain

f (x) = 2 x^{2} + x + 6, - 3 \leq x < 8

- 3 \leq x < 8

Interval Notation

[- 3, 8)

Solution steps

Set the domain to the given interval

- 3 \leq x < 8

The function has no undefined points nor domain constraints. Therefore, the domain is

- 3 \leq x < 8

x^{2} + 6

f (x) = (x^{2} + x) \cdot (x^{2} - 1)^{- 1}

f (x) = \frac{5 x - 2}{7 x + 14}

\frac{x - 1}{x ^{2} + 4 x - 5}

- lo g_{5} (x + 2)

What is the domain of f(x)=2x^2+x+6,-3<= x<8 ?
The domain of f(x)=2x^2+x+6,-3<= x<8 is -3<= x<8