What is the domain of y=(x^3-4x^2+x+6)/(x+1) ?

The domain of y=(x^3-4x^2+x+6)/(x+1) is x -1

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domain of y=(x^3-4x^2+x+6)/(x+1)

domain

y = \frac{x ^{3} - 4 x ^{2} + x + 6}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = \frac{ln ( x + 2 )}{x - 3}

\frac{4 x}{7 x - 3}

- 5 x + 3

f (x) = x (x - 3)^{\frac{1}{4}}

f (x) = \frac{ln ( x + 2 )}{x - 1}

What is the domain of y=(x^3-4x^2+x+6)/(x+1) ?
The domain of y=(x^3-4x^2+x+6)/(x+1) is x<-1\lor x>-1